SEARCH YOUR SOLUTION HERE  

Need Help(database backup)

,

May I ask on how will you back up a database via
cron jobs in an hourly basis

Posted On: Thursday 25th of October 2012 11:03:58 PM Total Views:  169
View Complete with Replies




Related Messages:

Restaraunt rating system - need help, will pay$!   (229 Views)
, I need to build a rating system for Restraunts where a patron can come, answer 5 questions (rate 1-5) each. Also, each restaruant can purchase an advertising package (basic to premier), what i need to be able to do now is on the front end, list restaraunts in a specific order. So a resturant with a 3 star rating with a premier package needs to come before a resturant with a 5 star rating with a basic package (for obvious reasons if someone is paying $40 a month they should be displayed before some getting a free listing). There are other senerios like "Category" and "City". My plan is to store the ratings in a separte table linked to the restaruant table by an id. I'm stumped on how can i average the ratings table first by id's and then tie it to the resturant table so that the sql knows OK "this resturant has a 3 star rating" and this resturant is a premier listing so order before the 5 star guy with a basic. I'm willing to pay for someone with the knowledge to help me work through the problems as i go. I have a 30 hour limit to do the project so it would be cheaper for me to pay someone to help then spend 60 hours trying to figure it all out. feel free to let me know how i can get in contact with you we can figure out how to go about it, and what you would charge to help me. Sorry the system won;t let me post my email since i'm a new user...
Got the foreign key blues... need help   (237 Views)
hey all. Either I have a funadmental misunderstanding of how foreign keys work, or something is wrong with mysql on my server. Here's a simplified version of what I'm trying to do: I have a client table: Code: CREATE TABLE `cp`.`CP_client` ( `id` int(10) unsigned NOT NULL auto_increment, `contact` varchar(45) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; and I have a user table: Code: CREATE TABLE `cp`.`CP_user` ( `id` int(10) unsigned NOT NULL auto_increment, `username` varchar(45) NOT NULL, `password` varchar(45) NOT NULL, PRIMARY KEY USING BTREE (`id`,`username`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; My Foreign key is basically the contact refences a user in the user table: Code: ALTER TABLE `cp`.`CP_client` ADD CONSTRAINT `FK_CP_client_1` FOREIGN KEY `FK_CP_client_1` (`contact`) REFERENCES `CP_user` (`username`) ON DELETE RESTRICT ON UPDATE RESTRICT; and the error I keep getting is this: MySQL Error Number 1005 Can't create table '/.cp/#sql-d1a_1d.frm (errno: 150) I've also tried creating the foreign key as a reference to the user id with the same outcome. Any idea what's going on
Page 2 - Query with subselect optimaization help needed!   (233 Views)
the subquery is correlated, which means it looks only at those rows where the bmn_logs.music.user is the same as the outer query's accounts.user so bmn_logs.music.user should have an index -- and you said that it does -- so whether the MAX() is on the id or on a datetime column doesn't matter, because it's the user that has to be filtered the only other thing i can think of is that instead of a subquery for the max(), you replace this with a join what's up with the STRAIGHT JOIN, what's that for
Comparing Tables...I need help.   (114 Views)
Let me set the scene for you. I have two tables on the same database: hr_harassment (everybody who has already entered into a training class) fields: lname, fname, class hr_employee_list (everybody who needs to enter into a training class) fields: Lname, Fname I need to compare the two tables to figure out who has not yet signed up for the class. What would be the easiest way to do this I am using PHP to program the page. I looked online and came up with this: SELECT * FROM hr_employee_list AND NOT EXISTS (SELECT * FROM hr_harrassment AND hr_employee_list.Lname = hr_harrassment.lname AND hr_employee_list.Fname = hr_harrassment.fname) But my browser tells me this: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in monitor.php on line 270
find lowest unique number in a column (was "SQL query help needed")   (158 Views)
Hi folk, Been working on a query whole day without progress so I hope someone of you experts can help me. I need to find the lowest unique number in a column: (Sorry dont know how to tag the code) (got a column name price and time) price time 5 2006-05-04:12:00:00 4 2006-05-04:12:00:04 5 2006-05-04:12:01:16 12 2006-05-04:12:02:54 4 2006-05-04:12:05:02 as you all can see is "12 2006-05-04:12:02:54" the lowest unique number. but how do I put this in a query
Some advice on performance needed   (278 Views)
I have two tables. One for products and one for reviews. I have setup a detail page which displays the various fields out of the products table and then looks for all reviews in the reviews table which match the products key and display the average. good so far. I want to have a page which displays a whole list of the products and show their rating next to them but I'm wondering if making it search the reviews table and calculate the average for 50 products in one go is going to cause a bit of a strain on the server Is there another way I can do this, perhaps storing the precalculated average in the products table but how would I go about doing that Or is this not a problem Any input you can offer would be very much appreciated. Thank You.
WHERE statement- ' ' needed?   (235 Views)
I have the following statement: Code: SELECT DISTINCT u.user_title, u.user_first_name, u.user_last_name, e.course_name, e.course_date FROM user_name AS u, course_enroll AS e, course_complete as c WHERE e.course_ID = c.course_ID AND e.course_date = c.course_date AND e.course_session = c.course_session AND e.user_ID = u.user_ID AND e.user_ID != c.user_ID ORDER BY e.course_date DESC, e.course_name ASC My problem is the "e.course_session = c.course_session" in the WHERE clause. Both of these fields are varchar types. With the current syntax, the appropriate matched records are not being found. I tried: 'e.course_session' = 'c.course_session' and no records were returned. The data that will populate these fields will be things like "Session 1". Any advice on how to clean this up to get the statement to pull the right recordset is much appreciated...
Database Tean needed for important project - Please Read!   (232 Views)
AnimalHelp Foundation is looking for some fabulous database developers for a very important pro-bono type job. If you have time to give for a really great cause, please contact Jodi Witte at jwitte@animalhelp.com to join the team! The Concept: Recent devestating hurricanes along the gulf coast have truly brought to light the inadequacies of a central system of animal record keeping and ultimately helping these displaced animals reunite with their families. There is NO central database that data can be easily entered by volunteers, and searched through by rescuers or pet owners. Petfinder.com has built a makeshift system that is helping, but is not great. If you visit http://disaster.petfinder.org/emergency/rescue/searchForm.cgitype=found and lets say you are looking for a solid black, 10 year old male german shepherd, you will find it is almost impossible to find your pet. Now, consider that this is not the only list of animals displaced due to Hurricane Katrina. These animals are spread out over 50 different databases such as http://www.badrap.org/rescue/katrina_dogs.cfm and http://katrinapets.shanonandmelanie.com/viewfound.asp. (The list of all known databases is available if you are interested). If that is not proof enough, I can send you a photo of a grey/black standard poodle which was picked up by a coast guard helicopter in New Orleans, then I can also include the list of all the databases. If this was your dog, would you find him I don't think so. I have tried. This dog I mention was in my care at the New Orleans airport as I received him off the helicopter. He sat for 2 days with me on the tarmac watching for his family to show up. While we were indoors, he would sit facing the door, just waiting. Nothing and no one could get his attention, he was so sure his owner would walk through the door. He was then moved to a shelter in Baton Rouge where I visited him again. He had given up and no longer was watching for them. But then he was moved again, and now despite my best efforts, I can't find him. I don't know where he was sent, which of the multiple shelters all over the US he has been taken. If I can't find him, then I can only conclude that his owners never will either. This is very sad!!! What happens after a disaster is many groups converge on an area and begin rescue. The animals are sheltered at a few main locations, with some smaller private home sheltering one or two animals, vet clinic and also boarding kennels also doing sheltering on a small scale. Each group uses their own intake forms, and then it often takes 3 to 4 weeks before data entry is started. The Solution: AnimalHelp Foundation will provide one central online database, digital cameras and laptop computers at every location, along with Directway satellite internet access and generators to power the computer equipment. AnimalHelp Foundation will also provide dedicated data entry volunteers at each location. Right from the beginning these animals are entered in the database and their locations tracked at every step. In the database all information will be entered by the volunteers, including sex, coloring, tags, collar color, location found, breed, etc... This database will be searchable by breed and color, or color alone, or any combination of description or information. It will be a high powered database, making it easy - because everything is there - for an owner to find their pet. Every pet will have a photo with their entry. Owners will also be able to add information on lost pets and the last known location. This database must be able to cross reference on each and every detail. Shelters and rescue groups must be able to pre-register before a disaster. Individuals who find an animal can register at that time. And, it will include a credit page with bios of the entire database team who gave their time and expertise to build this invaluable tool. I will need a team - the cream of the crop in database development. I know disaster response, I know what we need. But I need a database team, headed by someone who can lead and direct the team to make this the most powerful animal disaster tool ever. If you are willing to join this team, please contact me immediately. We need to get started because the disasters just keep happening...and the sooner we are ready, the better!!! I look forward to hearing from you! Jodi Witte President AnimalHelp Foundation jwitte@animalhelp.com Jodi Beck Witte currently works full time for AnimalHelp and is also a member of the Veterinary Medical Assistance Team (VMAT), part of the National Disaster Medical System, US Department of Homeland Security. In addition to her disaster response experience, she has worked as a veterinary technician in both small animal practice and at a zoo, and has done wildlife rehabilitation for many years. She is certified in Chemical Immobilization/Remote Capture, Large Animal Rescue, and is certified as a Weapons of Mass Destruction Specialist.
3 tables delete query. mysql geek need :)   (236 Views)
I have 3 tables! Need a MYSQL delete query to delete rows in 3 tables at same time... table1: log_visit 1) Need to DELETE from log_visit WHERE counter > 5 id | visit | visitor | counter 1 - 10 - qwerty | 15 2 - 11 - qwerty | 10 3 - 12 - azerty | 8 4 - 13 - azerty | 1 it will delete row 1 and 2 table2: log_link_visit_action 2) need to get visit and visitor rows deleted from table1 and delete in table2, in this case [row 1-table1] DELETE from log_link_visit_action WHERE visit = 10 AND visitor= querty [row 2-table1] DELETE from log_link_visit_action WHERE visit = 11 AND visitor=querty [row 3-table1] DELETE from log_link_visit_action WHERE visit = 12 AND visitor=azerty id | visit | visitor | url 15 - 8 - dodid - yahoo.com 16 - 10 - qwerty - google.com 17 - 11 - qwerty - abc.com 18 - 15 - kaz - zzz.com it will delete row 16 and 17 table3: log_action 3) Need to delete all url deleted in table2, in this case [row 17-table2] DELETE from log_action WHERE idaction = 'google.com' [row 18-table2] DELETE from log_action WHERE idaction = 'abc.com' id | idaction 1 - google.com 2 - yahoo.com 3 - abc.com it will delete row 1 and 3 Any possible help joining delete queries in one query would be extremely helpful Many
Join sintax help - not even know if I really need a join - please advice. :)   (313 Views)
all, This is a common scenario but I'm struggling here. I have 3 tables. The middle one relates table 1 and 3 by having a Fk from both tables. I would like to list some data from table 1 and same data from the table 3. But that data should be organized by ordering a given column in table 2. Can I have an example of the above, so that I can study and try to apply it to my code If you prefer, I can well provide the create tables here, I was just thinking that, like this, I can properly learn. K.
subquery max group needs and additional where clause   (300 Views)
I have a discussion forum that I would like to filter approved posts. I would like to know how to select the max(datetime) but only if the max has an approved value of 1. The only way I can think to do this is adding a where clause of approved = 1 but this will not work with a group by. Any suggestions Code MySQL: select * from questions where datetime in (select max(datetime) from questions group by id )
need help with simplifyling mysql queries.   (327 Views)
ok im really not sure what this is called so im making a new thread. in my current website i need to select photos using 3 different mysql calls, is there a way to simplify them into one mysql call there are 3 types of photos i need selected and they are related to the current photo and "report" thing, so far i have been doing it this way: Code MySQL: "SELECT id FROM photos WHERE seq > :seq and reportid=:reportid and seq NOT LIKE '0' ORDER BY seq ASC LIMIT 1"; "SELECT id FROM photos WHERE id < :fotoid and reportid=:reportid ORDER BY id ASC LIMIT 1"; "SELECT id FROM photos WHERE seq=( SELECT MAX(seq) FROM photos WHERE reportid=:reportid) and reportid=:reportid ORDER BY ID ASC LIMIT 1"; but now i started wondering if its a bit excessive and could be possibly simplified into 1 mysql query
CTE /w Multiple JOIN needs   (155 Views)
I'm using CTEs along with a JOIN to pull personnel information. This works fine. Now, I want to try to pull more information from another table, "Phones". Phones contains multiple phone numbers, of multiple types, for personnel. Each person's phone are also ranked in order of importance and they can have multiple phones of the same type (cell, home, work, etc). Phones PhoneID PersonnelID PhoneType PhoneNumber SequenceNo Now, what I'm trying to do is continue pulling all Personnel, but also the highest phone number of a particular type (optimally in the same SP). What I have so far: Code SQL: CREATE PROCEDURE dbo.Personnel_GetContactHelpSummariesByStartingNodeID ( @StartingNodeID INT, @PhoneType CHAR(3) ) AS WITH Nodes (NodeID, ParentNodeID, SequencePath) AS ( SELECT NodeID, ParentNodeID, SequencePath FROM Personnel_CommandHierarchy WHERE NodeID = @StartingNodeID UNION ALL SELECT CH.NodeID, CH.ParentNodeID, CH.SequencePath FROM Personnel_CommandHierarchy CH JOIN Nodes R ON R.NodeID = CH.ParentNodeID ) SELECT Personnel_Personnel.PersonnelID, Personnel_Personnel.FirstName, Personnel_Personnel.MiddleInitial, Personnel_Personnel.LastName, Personnel_Personnel.SuffixCode, Personnel_Personnel.CommandHierarchyNodeID, Personnel_Personnel.ServiceMember, Personnel_Phones.PhoneNumber, Personnel_CivilianPersonnel.CivilianClassificationCode, Personnel_CivilianPersonnel.CivilianRankCode, Personnel_ServicePersonnel.ServiceRankCode FROM Nodes INNER JOIN Personnel_Personnel ON Nodes.NodeID = Personnel_Personnel.CommandHierarchyNodeID LEFT OUTER JOIN Personnel_Phones ON Personnel_Personnel.PersonnelID = Personnel_Phones.PersonnelID INNER JOIN Personnel_CivilianPersonnel ON Personnel_CivilianPersonnel.PersonnelID = Personnel_Personnel.PersonnelID INNER JOIN Personnel_ServicePersonnel ON Personnel_ServicePersonnel.PersonnelID = Personnel_Personnel.PersonnelID WHERE Personnel_Personnel.CommandHierarchyNodeID = Nodes.NodeID AND Personnel_Personnel.Archived = 0 ORDER BY Nodes.SequencePath, Personnel_Personnel.LastName, Personnel_Personnel.FirstName RETURN Since I'm already using the WHERE clause to join my Personnel table to the table created by the CTE, I'm not sure where I can indicate that I only want the top-ranked phone number of a particular type.
simple database. just need some pointers.   (191 Views)
I there. I am currently working on a clients site that i think would benefit from a simple database. The site is a semi truck dealer all i would need is some way to display a list of trucks with pictures and a brief description. From there be able to click on a specific truck and view a details page with an expanded view of the truck, a bigger picture and more details. The most important thing is that what ever the information comes from the client needs to be able to update it him self. I have worked with mySQL and some php but really have almost no experience in those or any kind of CMS. can anyone point me in the direction of a tutorial or something that could help me learn how to make or adapt something to my needs.
need help with a query   (212 Views)
The relevant cols in my table are these. |Session_ID | referer | domain_viewed | (please don't worry about the upper and lower case. this is a test/practice db and I have learned about that issue. ;o I am trying to find out the total number of unique viewers (sessions), who were refered by referer AND who visited domain_viewed My query is like this but it gives seems to give me the total number of visitors referred irrespective of session. Code mysql: SELECT count(*) from tbl_Statistics where referer = 'www.refering_domain.com' and domain_viewed = 'www.our_domain.com' group by Session_ID How can I make sure that it returns say a composite result of 4 sessions :: 650 page views (total across those sessions) bazz
Help needed for query.   (231 Views)
Everybody, i want to know about how to retrieve value order by numeric and alphabetic words in one query e.g:- I have value in db like 1180A,1180B,1180C so how to get 1180A first then 1180B then 1180C
I need to update a large amount of values in 2 columsn in 1 table   (220 Views)
I have a table that I need to change all values for all rows in 2 columns (used for mapping products). Is there any SQL that will let me just say something like, update the 2 columns and insert these values in this order Example: these are the values: 2, 4, 6, 3, 4, 1, 3, 4 And those values would be inserted as the values for the first 8 rows Sorry, noob question probably Thank you
Complex SQL query - which statements do I need?   (168 Views)
I've got a table with over 1,000 entries. Those entries are category names for an eCommerce site. Each entry has cat_id and also cat_father_id. I'm trying to get information from within the one table which is like this: cat_father/cat_father/cat_father/cat Basically keep looking up in the table until all parent categories are identified so that I can build a URL to any particular category. What statements should I be looking at to get this
I need some guidace regarding ACCOUNTS table   (176 Views)
I am developing a website. That website will offer some products, registration fees and monthly fees etc. What i think is that to create a TABLE called "ACCOUNTS" and maintain records with following fields. This website will receive the payments in terms of REGISTRATION FEES / MONTHLY FEES AND PRODUCT PRICES and It will also pay the commissions to sellers etc. it is simple like a SALESMAN can register with suppose $100/- and can sale the products with this reference id. so that is how we will receive the payments, and he, the seller will earn from our site so we will pay to him as well. So we need to record both the transactions. RECEIVEs and PAYMENTs now, should I make separate table for the 2 transaction or i can make one table like follow : 0) transaction id 1) transaction date 2) description 3) debit /// to record the REVENUE 4) credit /// to record the EXPENSES 5) to_userid 6) from_userid 7) status please guide !
Stored Procedure needed   (187 Views)
I have a table named players with these fields: Code: playerid {int} teamid {int} jersey {int} playername {varchar(50)} age {int} And a table named pitchcounts with these fields: Code: id {int} gamenum {int} playerid {int} pitchcount {int} Now, what I need is a stored procedure to return the number of pitches each player pitched in a week where the weekno is passed and the days rest required and next availability date of the pitcher based on the criteria below: Code: In-House Ages 13-16 (Babe Ruth) -------------------------------------------------------- Pitches Days Rest ------------------------------- 0-20 0 Rest 21-40 1 Rest 41-60 2 Rest 61-95 3 Rest ******************************************************** In-House Ages 11 & 12 (Majors-American, National & Continental) -------------------------------------------------------- Pitches Days Rest ------------------------------- 0-20 0 Rest 21-40 1 Rest 41-60 2 Rest 61-85 3 Rest No more than 125 pitches in a week. 4 12's can pitch but no more than 240 pitches no matter how many games in a week. ******************************************************** Travel Ages 8, 9, 10, 11 & 12 -------------------------------------------------------- Player can pitch up to three innings in a weekend. Two innings doesn't affect In-House the next day, but prior In-House pitching does apply. If 61 or more pitches on Thurs or Sat no travel that weekend. A travel manager must obtain approval from the In-House manager in order to pitch a player for more than one inning if the in-house team has a game following the travel team on the same day. If pitchers does pitch more than 1 inning in travel, pitcher limited to 60 pitches In-House. If travel follows In-House on same day, player can pitch in travel if no more than 60 pitches thrown in-house. These rules will be in place until may 1st. We want these rules to be followed in spirit as well as literally. If abuses are found, even if within rules, we will change them after may 1st. Under no circumstances is a player able to be made ineligible for In-House play. Code: ******************************************************** In-House Ages 10 and 9'S in Majors (Majors American, National, Continental) -------------------------------------------------------- Pitches Days Rest ------------------------------- 0-20 0 Rest 21-40 1 Rest 41-60 2 Rest 61-75 3 Rest ******************************************************** Double A In-House (AA) -------------------------------------------------------- No more than 40 pitches in a game or 80 for a week. ******************************************************** Additional In-House Notes -------------------------------------------------------- If a pitcher gets to 85 (75 at age 10) pitches in a game in the middle of a batter, they can finish the batter only. Pitching results must be reported by email to Director within 24 hours of the game by the winning manager. Pitcher can not re-enter to pitch in the same In-House game once removed from the mound. Pitcher receives seven warm-up pitches before their first inning on mound and five every inning thereafter. Warmup pitches no not count toward total counts. Pitches to final batter, if count gets past game or week totals, don't count toward totals. 12 year olds in Continental League can not pitch. Rest Examples: Code: if 20 or less on Monday, available on Tuesday if 21-40 on Monday, available on Wednesday if 41-60 on Monday, available on Thursday if 61 or more on Monday, available on Friday