Wrapper functions and arguments

One little issue I have is to write a little wrapper which can generally
pass standard and keyword arguments to a callee:

def a(x, y, z):
print x, y, z
def b(x, y, z='fruitbat')
print x, y, z

for func in a, b:
def wrapper(func=func, *args, **argsk):
# do something
func(*args, **argsk)

x[0](1, 2, 3)
x[1](1, 2)

Is there any way to do this Can you capture arguments in a tuple and dict,
but still receive other keyword arguments The only solution I found was to
implement wrapper as a class (like I would in c++):

class wrapper(object):
def __init__(self, func):
self.func = func
def __call__(self, *args, **argsk):
self.func(*args, **argsk)


Jeremy Sanders

Posted On: Monday 5th of November 2012 02:26:48 AM Total Views:  558
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